Let's express each log in terms of a common base.
log3 27 = log3 (3^3) = 3 log3 3 = 3*1 = 3
log2 64 = log2 (2^6) = 6 log2 2 = 6*1 = 6
log5 25 = log5 (5^2) = 2 log5 5 = 2*1 = 2
Now substitute these values back into the expression:
3 - 6 + 2 = -1
Therefore, log3 27 - log2 64 + log5 25 = -1.
Let's express each log in terms of a common base.
log3 27 = log3 (3^3) = 3 log3 3 = 3*1 = 3
log2 64 = log2 (2^6) = 6 log2 2 = 6*1 = 6
log5 25 = log5 (5^2) = 2 log5 5 = 2*1 = 2
Now substitute these values back into the expression:
3 - 6 + 2 = -1
Therefore, log3 27 - log2 64 + log5 25 = -1.