To solve this system of equations:
1) x - 2a = 302) 2z + y = 303) 6z = 304) 2y - a = 305) f + 3z = 30
We will first solve equations 2, 3 and 5 to find the values of y, z, and f:
From equation 3:6z = 30z = 30/6z = 5
Substitute z = 5 into equation 2:2(5) + y = 3010 + y = 30y = 30 - 10y = 20
Substitute z = 5 into equation 5:f + 3(5) = 30f + 15 = 30f = 30 - 15f = 15
Now that we have found the values of y, z, and f, let's substitute them back into equations 1 and 4 to solve for x and a:
From equation 1:x - 2a = 30x - 2a = 30x - 2(15) = 30x - 30 = 30x = 30 + 30x = 60
From equation 4:2y - a = 302(20) - a = 3040 - a = 30-a = 30 - 40-a = -10a = 10
Therefore, the solution to the system of equations is:x = 60y = 20z = 5f = 15a = 10
To solve this system of equations:
1) x - 2a = 30
2) 2z + y = 30
3) 6z = 30
4) 2y - a = 30
5) f + 3z = 30
We will first solve equations 2, 3 and 5 to find the values of y, z, and f:
From equation 3:
6z = 30
z = 30/6
z = 5
Substitute z = 5 into equation 2:
2(5) + y = 30
10 + y = 30
y = 30 - 10
y = 20
Substitute z = 5 into equation 5:
f + 3(5) = 30
f + 15 = 30
f = 30 - 15
f = 15
Now that we have found the values of y, z, and f, let's substitute them back into equations 1 and 4 to solve for x and a:
From equation 1:
x - 2a = 30
x - 2a = 30
x - 2(15) = 30
x - 30 = 30
x = 30 + 30
x = 60
From equation 4:
2y - a = 30
2(20) - a = 30
40 - a = 30
-a = 30 - 40
-a = -10
a = 10
Therefore, the solution to the system of equations is:
x = 60
y = 20
z = 5
f = 15
a = 10