1. (х+4)*(х-3) _____________ >0 х+4 2. 0,6 2x+5 >0,6 4x

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вопрос

(х+4)*(х-3) >
This is a quadratic equation in the form of (x+a)(x+b), where a=4 and b=-3
To find the values of x that make the expression greater than 0, we need to determine the signs of the factors (x+4) and (x-3) separately.

For (x+4) to be greater than 0, x must be greater than -4
For (x-3) to be greater than 0, x must be greater than 3.

Therefore, the solution is x > 4.

0.6(2x+5) > 0.6(4x
Multiply both sides by 10 to eliminate the decimals
6(2x+5) > 6(4x
12x + 30 > 24
Subtract 12x from both sides
30 > 12
Divide by 12
2.5 > x

Therefore, x is greater than 2.5.