To solve for y, first factor out the numerator and denominator:
(3y^3 - 12y^2 - y + 4) / (9y^4 - 1) = 0
Numerator: (3y^3 - 12y^2 - y + 4) = y^2(3y - 12) - 1(3y - 4) = (y^2 - 1)(3y - 4)
Denominator: (9y^4 - 1) = (3y^2 + 1)(3y^2 - 1) = (3y^2 + 1)(√3y - 1)(√3y + 1)
Now, the equation becomes:
((y^2 - 1)(3y - 4)) / ((3y^2 + 1)(√3y - 1)(√3y + 1)) = 0
Setting the numerator equal to 0:
(y^2 - 1)(3y - 4) = 0
This equation can be solved by setting each factor equal to 0:
y^2 - 1 = 0y^2 = 1y = ±1
3y - 4 = 03y = 4y = 4/3
Hence, the possible solutions for the equation are y = 1, y = -1, y = 4/3.
To solve for y, first factor out the numerator and denominator:
(3y^3 - 12y^2 - y + 4) / (9y^4 - 1) = 0
Numerator: (3y^3 - 12y^2 - y + 4) = y^2(3y - 12) - 1(3y - 4) = (y^2 - 1)(3y - 4)
Denominator: (9y^4 - 1) = (3y^2 + 1)(3y^2 - 1) = (3y^2 + 1)(√3y - 1)(√3y + 1)
Now, the equation becomes:
((y^2 - 1)(3y - 4)) / ((3y^2 + 1)(√3y - 1)(√3y + 1)) = 0
Setting the numerator equal to 0:
(y^2 - 1)(3y - 4) = 0
This equation can be solved by setting each factor equal to 0:
y^2 - 1 = 0
y^2 = 1
y = ±1
3y - 4 = 0
3y = 4
y = 4/3
Hence, the possible solutions for the equation are y = 1, y = -1, y = 4/3.