1)2x+15x+5=0 2)4x^2+3x-2=0

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вопрос

1) To solve the equation 2x + 15x + 5 = 0, first combine the like terms:

2x + 15x + 5 = 0
17x + 5 = 0

Subtract 5 from both sides:

17x = -5

Divide by 17:

x = -5/17

Therefore, the solution to the equation 2x + 15x + 5 = 0 is x = -5/17.

2) To solve the equation 4x^2 + 3x - 2 = 0, you can use the quadratic formula:

x = [-b ± √(b^2 - 4ac)] / 2a

In this case, a = 4, b = 3, and c = -2. Substituting into the quadratic formula:

x = [-3 ± √((3)^2 - 4 4 (-2))] / 2 * 4
x = [-3 ± √(9 + 32)] / 8
x = [-3 ± √41] / 8

Therefore, the solutions to the equation 4x^2 + 3x - 2 = 0 are x = (-3 + √41) / 8 and x = (-3 - √41) / 8.