To solve this equation, we need to use the trigonometric identity:
cos(π/2 + x) = sin(π/2 - (π/2 + x)) = sin(-π/2 - x)
So, the equation becomes:
sin(-π/2 - x) = sin(-π/6)
Since sine function is an odd function, sin(-θ) = -sin(θ), so we can rewrite the equation as:
-sin(π/2 + x) = sin(-π/6)
Using the fact that sin(π/2 + x) = cos(x), the equation simplifies to:
-cos(x) = sin(-π/6)
Since sin(-π/6) = -1/2, the equation becomes:
-cos(x) = -1/2
Multiplying both sides by -1, we get:
cos(x) = 1/2
Therefore, x is equal to π/3 or 60 degrees.
To solve this equation, we need to use the trigonometric identity:
cos(π/2 + x) = sin(π/2 - (π/2 + x)) = sin(-π/2 - x)
So, the equation becomes:
sin(-π/2 - x) = sin(-π/6)
Since sine function is an odd function, sin(-θ) = -sin(θ), so we can rewrite the equation as:
-sin(π/2 + x) = sin(-π/6)
Using the fact that sin(π/2 + x) = cos(x), the equation simplifies to:
-cos(x) = sin(-π/6)
Since sin(-π/6) = -1/2, the equation becomes:
-cos(x) = -1/2
Multiplying both sides by -1, we get:
cos(x) = 1/2
Therefore, x is equal to π/3 or 60 degrees.