3(х+у)+4,5х=11/у-2=1/хрешить систему

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вопрос

To solve this system of equations, we first need to simplify the expressions:

1) 3(х+у) + 4,5х = 11
2) 1/у - 2 = 1/х

Let's solve each equation separately:

1) Simplify the first equation:

3(х+у) + 4,5х = 11
3х + 3у + 4,5х = 11
7,5х + 3у = 11

2) Simplify the second equation:

1/у - 2 = 1/х
Multiply by у and х to get rid of the fractions:
х - 2у = у
х - у = 2у
x = 3у

Now we have x = 3y. Substitute x = 3y into the first equation:

7,5(3у) + 3у = 11
22,5у + 3y = 11
25,5y = 11
y = 11 / 25,5
y = 0,431

Then, substitute y = 0,431 into x = 3y:

x = 3*0,431
x = 1.293

Therefore, the solution to the system of equations is:
x = 1.293
y = 0.431