7x+2=3x-10 2x-три пятых=три четвёртых х- одна вторая

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вопрос

To solve the first equation:

7x + 2 = 3x - 10
Subtract 3x from both sides:
7x - 3x + 2 = -10
Combine like terms:
4x + 2 = -10
Subtract 2 from both sides:
4x = -12
Divide by 4:
x = -3

To solve the second equation:

2x - (3/5) = (3/4)
Add (3/5) to both sides:
2x = (3/4) + (3/5)
Convert fractions to have a common denominator:
2x = (15/20) + (12/20)
2x = 27/20
Divide by 2:
x = 27/40

Therefore, the solutions to the equations are x = -3 and x = 27/40.