(x-4)^2 - 6 = (2 + x)^Expanding both sides:
(x^2 - 8x + 16) - 6 = (4 + 4x + x^2x^2 - 8x + 10 = 4 + 4x + x^Rearranging terms:
-8x - 4x = 4 - 1-12x = -Dividing by -12:
x = 1/2
Ответ: x = 1/2
(x-4)^2 - 6 = (2 + x)^
Expanding both sides:
(x^2 - 8x + 16) - 6 = (4 + 4x + x^2
x^2 - 8x + 10 = 4 + 4x + x^
Rearranging terms:
-8x - 4x = 4 - 1
-12x = -
Dividing by -12:
x = 1/2
Ответ: x = 1/2