To find the value of "a", we need to expand the right side of the equation and compare it to the left side.
Given: x^2 + 6x - 27 = (x + 9)(x - a)
Expanding the right side(x + 9)(x - a) = x^2 - ax + 9x - 9= x^2 + (9-a)x - 9a
Comparing the expanded right side to the left sidex^2 + 6x - 27 = x^2 + (9-a)x - 9a
To find the value of "a", we compare the coefficients of the terms6x = (9-a)x, and -27 = -9a
From the first equation6 = 9 - a = 9 - a = 3
Therefore, a = 3.
To find the value of "a", we need to expand the right side of the equation and compare it to the left side.
Given: x^2 + 6x - 27 = (x + 9)(x - a)
Expanding the right side
(x + 9)(x - a) = x^2 - ax + 9x - 9
= x^2 + (9-a)x - 9a
Comparing the expanded right side to the left side
x^2 + 6x - 27 = x^2 + (9-a)x - 9a
To find the value of "a", we compare the coefficients of the terms
6x = (9-a)x, and -27 = -9a
From the first equation
6 = 9 -
a = 9 -
a = 3
Therefore, a = 3.