(X^3-8X^2+7X)/(1-X)=0

Предыдущий
вопрос Следующий
вопрос

To solve the given equation, we first need to set the numerator of the fraction equal to zero and solve for the values of x.

So, we have:

X^3 - 8X^2 + 7X = 0

Factoring out an X from the equation:

X(X^2 - 8X + 7) = 0

Now, we can factor the quadratic expression inside the parentheses:

X(X - 7)(X - 1) = 0

Setting each factor equal to zero:

X = 0, X = 7, X = 1

Now, we need to check which of these values make the denominator zero, as dividing by zero is undefined.

Checking each value:

1 - 0 = 1 (Valid)
1 - 7 = -6 (Valid)
1 - 1 = 0 (Invalid)

Therefore, the solutions to the equation (X^3 - 8X^2 + 7X)/(1-X) = 0 are X=0 and X=7.