To solve the given equation, we first need to set the numerator of the fraction equal to zero and solve for the values of x.
So, we have:
X^3 - 8X^2 + 7X = 0
Factoring out an X from the equation:
X(X^2 - 8X + 7) = 0
Now, we can factor the quadratic expression inside the parentheses:
X(X - 7)(X - 1) = 0
Setting each factor equal to zero:
X = 0, X = 7, X = 1
Now, we need to check which of these values make the denominator zero, as dividing by zero is undefined.
Checking each value:
1 - 0 = 1 (Valid1 - 7 = -6 (Valid1 - 1 = 0 (Invalid)
Therefore, the solutions to the equation (X^3 - 8X^2 + 7X)/(1-X) = 0 are X=0 and X=7.
To solve the given equation, we first need to set the numerator of the fraction equal to zero and solve for the values of x.
So, we have:
X^3 - 8X^2 + 7X = 0
Factoring out an X from the equation:
X(X^2 - 8X + 7) = 0
Now, we can factor the quadratic expression inside the parentheses:
X(X - 7)(X - 1) = 0
Setting each factor equal to zero:
X = 0, X = 7, X = 1
Now, we need to check which of these values make the denominator zero, as dividing by zero is undefined.
Checking each value:
1 - 0 = 1 (Valid
1 - 7 = -6 (Valid
1 - 1 = 0 (Invalid)
Therefore, the solutions to the equation (X^3 - 8X^2 + 7X)/(1-X) = 0 are X=0 and X=7.