To solve this system of equations, we can use the method of elimination.
Let's start by multiplying the first equation by 4 and the second equation by -3 to eliminate the y variable:
4(2x + 3y) = 4(-1-3(5x + 4y) = -3(1)
This gives us:
8x + 12y = --15x - 12y = -3
Now, add these two equations together to eliminate the y variable:
8x + 12y - 15x - 12y = -4 - -7x = -7
Divide by -7 on both sides:
x = 1
Now, substitute x = 1 back into one of the original equations to solve for y. Let's use the first equation:
2(1) + 3y = -2 + 3y = -3y = -y = -1
Therefore, the solution to the system of equations is x = 1 and y = -1.
To solve this system of equations, we can use the method of elimination.
Let's start by multiplying the first equation by 4 and the second equation by -3 to eliminate the y variable:
4(2x + 3y) = 4(-1
-3(5x + 4y) = -3(1)
This gives us:
8x + 12y = -
-15x - 12y = -3
Now, add these two equations together to eliminate the y variable:
8x + 12y - 15x - 12y = -4 -
-7x = -7
Divide by -7 on both sides:
x = 1
Now, substitute x = 1 back into one of the original equations to solve for y. Let's use the first equation:
2(1) + 3y = -
2 + 3y = -
3y = -
y = -1
Therefore, the solution to the system of equations is x = 1 and y = -1.