First, we need to distribute the terms in the expression:
(n+2)(n+3) = n^2 + 3n + 2n + 6 = n^2 + 5n + 6
(n-6)(n-1) = n^2 - n - 6n + 6 = n^2 - 7n + 6
Now subtract the second expression from the first:
(n^2 + 5n + 6) - (n^2 - 7n + 6)= n^2 + 5n + 6 - n^2 + 7n - 6= 5n + 7n= 12n
Therefore, (n+2)(n+3)-(n+6)(n-1) simplifies to 12n.
First, we need to distribute the terms in the expression:
(n+2)(n+3) = n^2 + 3n + 2n + 6 = n^2 + 5n + 6
(n-6)(n-1) = n^2 - n - 6n + 6 = n^2 - 7n + 6
Now subtract the second expression from the first:
(n^2 + 5n + 6) - (n^2 - 7n + 6)
= n^2 + 5n + 6 - n^2 + 7n - 6
= 5n + 7n
= 12n
Therefore, (n+2)(n+3)-(n+6)(n-1) simplifies to 12n.