Д1+3i/2-i = (1+3i)(2+i)/(2-i)(2+i= (2+i+6i+3i^2)/(4-i^2= (2+7i-3)/(4+1= -1+7i/= -1/5 + 7/5*i
А(4+5i)(4-5i) = 44 + 4(-5i) + 5i4 - 5i(-5i= 16 - 20i + 20i + 2= 41
Д
1+3i/2-i = (1+3i)(2+i)/(2-i)(2+i
= (2+i+6i+3i^2)/(4-i^2
= (2+7i-3)/(4+1
= -1+7i/
= -1/5 + 7/5*i
А
(4+5i)(4-5i) = 44 + 4(-5i) + 5i4 - 5i(-5i
= 16 - 20i + 20i + 2
= 41