To solve this equation, we need to first combine all fractions on one side of the equation and simplify.
Given equation: 2y - 8/(y-5) + 10/(y^2-25) = y + 4/(y+5)
To simplify, we first need to factor the denominator in the second term on the left side:
y^2 - 25 = (y + 5)(y - 5)
Now substitute back into the equation:
2y - 8/(y-5) + 10/[(y + 5)(y - 5)] = y + 4/(y+5)
Find a common denominator for all terms:
2y(y+5)/(y+5)(y-5) - 8(y+5)/(y+5)(y-5) + 10/(y+5)(y-5) = y(y-5)/(y+5)(y-5) + 4(y-5)/(y+5)(y-5)
Simplify:
(2y^2 + 10y - 8y - 40 + 10) = (y^2 - 5y + 4y -20)
Combine like terms:
2y^2 + 2y - 30 = y^2 - y - 20
Rearrange into standard form:
2y^2 + 2y - 30 - y^2 + y + 20 = 0
y^2 + 3y - 10 = 0
Now factor or use the quadratic formula to solve for y.
To solve this equation, we need to first combine all fractions on one side of the equation and simplify.
Given equation: 2y - 8/(y-5) + 10/(y^2-25) = y + 4/(y+5)
To simplify, we first need to factor the denominator in the second term on the left side:
y^2 - 25 = (y + 5)(y - 5)
Now substitute back into the equation:
2y - 8/(y-5) + 10/[(y + 5)(y - 5)] = y + 4/(y+5)
Find a common denominator for all terms:
2y(y+5)/(y+5)(y-5) - 8(y+5)/(y+5)(y-5) + 10/(y+5)(y-5) = y(y-5)/(y+5)(y-5) + 4(y-5)/(y+5)(y-5)
Simplify:
(2y^2 + 10y - 8y - 40 + 10) = (y^2 - 5y + 4y -20)
Combine like terms:
2y^2 + 2y - 30 = y^2 - y - 20
Rearrange into standard form:
2y^2 + 2y - 30 - y^2 + y + 20 = 0
y^2 + 3y - 10 = 0
Now factor or use the quadratic formula to solve for y.