Let's first expand the left side of the equation:

(x+3)(x-2)(x-3)(x+2) = (x^2 + x - 6)(x^2 - 5)
= x^4 - 5x^2 + x^3 - 5x - 6x^2 + 30
= x^4 + x^3 - 11x^2 - 5x + 30

Now let's substitute this back into the original equation:

(x^4 + x^3 - 11x^2 - 5x + 30) - 5 = 6x - 7

Simplifying further:

x^4 + x^3 - 11x^2 - 5x + 30 - 5 = 6x - 7
x^4 + x^3 - 11x^2 - 5x + 25 = 6x - 7

Therefore, the equation is:

x^4 + x^3 - 11x^2 - 5x - 6x + 25 + 7 = 0
x^4 + x^3 - 11x^2 - 11x + 32 = 0

This is the final expanded form of the given equation.