A)4-3x≥x+16 б)7x+1>2x-9

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вопрос

A)

4 - 3x ≥ x + 16

First, let's simplify the equation by combining like terms:

4 - 3x ≥ x + 16
4 - 3x - x ≥ 16
4 - 4x ≥ 16
-4x ≥ 12

Next, divide by -4 to solve for x:

x ≤ -3

Therefore, the solution for the inequality 4 - 3x ≥ x + 16 is x ≤ -3.

B)

7x + 1 > 2x - 9

First, let's simplify the equation by combining like terms:

7x + 1 > 2x - 9
5x + 1 > -9

Next, isolate x by subtracting 1 from both sides:

5x > -10

Then, divide by 5 to solve for x:

x > -2

Therefore, the solution for the inequality 7x + 1 > 2x - 9 is x > -2.