To solve this equation, we can start by factoring out a common factor of 2:
2(3x^5 - 3x^4 - 4x^3 + 8x^2 - 8x + 16) = 0
Now, let's reorganize the terms within the parentheses:
2(x^3(3x^2 - 3x - 4) + 8(x^2 - x + 2)) = 0
Now we can factor the quadratic terms in the parentheses:
2(x^3(3x + 1)(x - 4) + 8(x - 2)(x - 1)) = 0
This gives us two possible solutions:
x = -1/3, 4, 2, 1
To solve this equation, we can start by factoring out a common factor of 2:
2(3x^5 - 3x^4 - 4x^3 + 8x^2 - 8x + 16) = 0
Now, let's reorganize the terms within the parentheses:
2(3x^5 - 3x^4 - 4x^3 + 8x^2 - 8x + 16) = 0
2(x^3(3x^2 - 3x - 4) + 8(x^2 - x + 2)) = 0
Now we can factor the quadratic terms in the parentheses:
2(x^3(3x + 1)(x - 4) + 8(x - 2)(x - 1)) = 0
This gives us two possible solutions:
x = -1/3, 4, 2, 1