1) 1/(∛b √b) = 1/((b^(1/3) b^(1/2)) = 1/(b^(1/3 + 1/2)) = 1/b^(5/6) = b^(-5/6)
2) (∛8 √27) / ∛216 = (2 3) / 6 = 6 / 6 = 1
3) d^(2+1/2) = d^(5/2) = d^(2.5)
1) 1/(∛b √b) = 1/((b^(1/3) b^(1/2)) = 1/(b^(1/3 + 1/2)) = 1/b^(5/6) = b^(-5/6)
2) (∛8 √27) / ∛216 = (2 3) / 6 = 6 / 6 = 1
3) d^(2+1/2) = d^(5/2) = d^(2.5)