To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve the first equation for y in terms of x3x - y = 1-y = -3x + 1y = 3x - 11
Now we can substitute this expression for y into the second equation5x + 6(3x - 11) = 25x + 18x - 66 = 223x - 66 = 223x = 9x = 92/2x = 4
Now that we have found the value of x, we can substitute it back into the equation we found for yy = 3(4) - 1y = 12 - 1y = 1
Therefore, the solution to the system of equations is x = 4 and y = 1.
To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve the first equation for y in terms of x
3x - y = 1
-y = -3x + 1
y = 3x - 11
Now we can substitute this expression for y into the second equation
5x + 6(3x - 11) = 2
5x + 18x - 66 = 2
23x - 66 = 2
23x = 9
x = 92/2
x = 4
Now that we have found the value of x, we can substitute it back into the equation we found for y
y = 3(4) - 1
y = 12 - 1
y = 1
Therefore, the solution to the system of equations is x = 4 and y = 1.