To solve this system of equations, we can expand the expressions on the left side of each equation:
(4x+5)2 = 16x^2 + 40x + 25 = 10y(5x+4)2 = 25x^2 + 40x + 16 = 10y
Now, we can set the two expressions equal to each other:
16x^2 + 40x + 25 = 25x^2 + 40x + 16
Subtract 25x^2 and 40x from both sides:
16 = 9x^2
Divide by 9:
x^2 = 16/9x = ±4/3
Now that we have found the value of x, we can substitute it back into one of the original equations to find y. Let's use the first equation:
(4*(4/3) + 5)^2 = 10y(16/3 + 5)^2 = 10y(31/3)^2 = 10y961/9 = 10yy = 961/90
Therefore, the solutions to the system of equations are x = ±4/3 and y = 961/90.
To solve this system of equations, we can expand the expressions on the left side of each equation:
(4x+5)2 = 16x^2 + 40x + 25 = 10y
(5x+4)2 = 25x^2 + 40x + 16 = 10y
Now, we can set the two expressions equal to each other:
16x^2 + 40x + 25 = 25x^2 + 40x + 16
Subtract 25x^2 and 40x from both sides:
16 = 9x^2
Divide by 9:
x^2 = 16/9
x = ±4/3
Now that we have found the value of x, we can substitute it back into one of the original equations to find y. Let's use the first equation:
(4*(4/3) + 5)^2 = 10y
(16/3 + 5)^2 = 10y
(31/3)^2 = 10y
961/9 = 10y
y = 961/90
Therefore, the solutions to the system of equations are x = ±4/3 and y = 961/90.