To solve this equation, we can first factor out (2-x) from each term:

(2-x) [(2-x)^2 + (2-x)x + 4] = 0

Expand the terms inside the brackets:

(2-x) [ (4 - 4x + x^2) + (2x - x^2) + 4 ] = 0

(2-x) [ 4 - 4x + x^2 + 2x - x^2 + 4 ] = 0

(2-x) [ 8 - 2x ] = 0

Now we have two possible solutions:

2-x = 0
x = 2

8 - 2x = 0
2x = 8
x = 4

Therefore, the solutions to the equation (2-x)^3 + (2-x)^2*x + 4(2-x) = 0 are x = 2 and x = 4.