Log[1/3,(7-x)] > -2 Log[2,(3-2x] < log[2,13]

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To solve this inequality, we need to first rewrite it in exponential form:

Next, we need to simplify the inequality:

2^(-1/Log[2, (7-x)]) > (3-2x)^(-2)
1/2^(1/Log[2, (7-x)]) > 1/(3-2x)^2

Now, we can rewrite the inequality in exponential form:

Log[2, (7-x)] < 2
7-x < 2^2
7-x < 4
-x < -3
x > 3

Therefore, the solution to the inequality is x > 3.