To solve the equations:
1) (3×m - 20) ÷ 5 = 503m - 20 = 50 × 53m - 20 = 2503m = 250 + 203m = 270m = 270 ÷ 3m = 90
2) 480 ÷ (13 - t) + 20 = 100480 ÷ (13 - t) = 100 - 20480 ÷ (13 - t) = 80480 = 80(13 - t)480 = 1040 - 80t80t = 1040 - 48080t = 560t = 560 ÷ 80t = 7
So the solutions are:m = 90t = 7
To solve the equations:
1) (3×m - 20) ÷ 5 = 50
3m - 20 = 50 × 5
3m - 20 = 250
3m = 250 + 20
3m = 270
m = 270 ÷ 3
m = 90
2) 480 ÷ (13 - t) + 20 = 100
480 ÷ (13 - t) = 100 - 20
480 ÷ (13 - t) = 80
480 = 80(13 - t)
480 = 1040 - 80t
80t = 1040 - 480
80t = 560
t = 560 ÷ 80
t = 7
So the solutions are:
m = 90
t = 7