(х+2)(х-6)-(х-7)(х+7)<30-3х

Предыдущий
вопрос Следующий
вопрос

First, let's expand both sides of the inequality:

Left side:
(х+2)(х-6) - (х-7)(х+7)
= x^2 - 6x + 2x - 12 - (x^2 + 7x - 7x - 49)
= x^2 - 6x + 2x - 12 - x^2 - 7x + 7x + 49
= x^2 - 4x - 12 - x^2 + 49
= -4x + 37

Right side:
30 - 3x

Now, we can rewrite the inequality with the expanded expressions:

-4x + 37 < 30 - 3x

Next, let's simplify the inequality:

-4x + 37 < 30 - 3x
-4x + 37 + 3x < 30
-x + 37 < 30
-x < -7
x > 7

Therefore, the solution to the inequality is x > 7.