1)Y=-cosx+2, x0=π/3 2)Y=tgx+4, x0=-π/4

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вопрос

1) To find the value of y when x = π/3 for the equation y = -cosx + 2:

y = -cos(π/3) + 2
y = -(1/2) + 2
y = 2 - 1/2
y = 1.5

Therefore, when x = π/3, y = 1.5.

2) To find the value of y when x = -π/4 for the equation y = tanx + 4:

y = tan(-π/4) + 4
y = -1 + 4
y = 3

Therefore, when x = -π/4, y = 3.