(х+2)(х+7)-х(х+5)=26

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вопрос

Let's expand the left side of the equation first:

(х+2)(х+7) - х(х+5
= х^2 + 7х + 2х + 14 - х^2 - 5
= х^2 + 9х + 14 - х^2 - 5
= 4х + 14

Now, set this expression equal to 26:

4х + 14 = 26

Subtract 14 from both sides:

4х = 12

Divide by 4:

х = 3

Therefore, the solution to the equation (х + 2)(х + 7) - х(х + 5) = 26 is х = 3.