1.) ||x-2|=5 2.) ||2x-12|+4|=8

Предыдущий
вопрос Следующий
вопрос

1.) To solve ||x-2|=5, we need to consider two cases
i) x-2 =
ii) x-2 = -5

i) x-2 =
Adding 2 to both sides
x = 7

ii) x-2 = -
Adding 2 to both sides
x = -3

Therefore, the solutions to ||x-2|=5 are x = 7 and x = -3.

2.) To solve ||2x-12|+4|=8, we again consider two cases
i) 2x-12+4 =
ii) -(2x-12)+4 = 8

i) 2x-8 =
Adding 8 to both sides
2x = 1
Dividing by 2
x = 8

ii) -(2x-12)+4 =
-2x + 12 + 4 =
-2x + 16 =
Subtracting 16 from both sides
-2x = -
Dividing by -2
x = 4

Therefore, the solutions to ||2x-12|+4|=8 are x = 8 and x = 4.