(y-3)(5+2y)-(5-2y)^2=Expanding the terms5y + 2y^2 - 15 - 6y - (25 - 20y + 4y^2) = Combine like terms2y^2 + 5y - 15 - 6y - 25 + 20y - 4y^2 = -2y^2 + 19y - 40 = Rearrange the terms2y^2 - 19y + 40 = Factor the quadratic equation(2y - 5)(y - 8) = y = 5/2 or y = 8
Therefore, the solutions to the equation are y = 5/2 or y = 8.
(y-3)(5+2y)-(5-2y)^2=
Expanding the terms
5y + 2y^2 - 15 - 6y - (25 - 20y + 4y^2) =
Combine like terms
2y^2 + 5y - 15 - 6y - 25 + 20y - 4y^2 =
-2y^2 + 19y - 40 =
Rearrange the terms
2y^2 - 19y + 40 =
Factor the quadratic equation
(2y - 5)(y - 8) =
y = 5/2 or y = 8
Therefore, the solutions to the equation are y = 5/2 or y = 8.