x + 5 - \frac{1}{x+3} \cdot (x^2 - 9)
= x + 5 - \frac{1}{x+3} \cdot (x+3)(x-3)
= x + 5 - (x-3)
= x + 5 - x + 3
= 8
x + 5 - \frac{1}{x+3} \cdot (x^2 - 9)
= x + 5 - \frac{1}{x+3} \cdot (x+3)(x-3)
= x + 5 - (x-3)
= x + 5 - x + 3
= 8