X²+4x-5= 0????X²-5x+7=0????4x²-12x+9=0???

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вопрос

The first equation can be solved by factoring or using the quadratic formula:

x² + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1

The second equation can be solved using the quadratic formula:

x² - 5x + 7 = 0
x = [5 ± √(25 - 4*7)] / 2
x = [5 ± √(25 - 28)] / 2
x = [5 ± √(-3)] / 2
x = (5 ± i√3) / 2
x = 2.5 ± 0.87i

The third equation can be solved by factoring or using the quadratic formula:

4x² - 12x + 9 = 0
(2x - 3)(2x - 3) = 0
(2x - 3)² = 0
2x - 3 = 0
2x = 3
x = 3/2 = 1.5

So the solutions to each equation are:
x = -5 or x = 1
x = 2.5 ± 0.87i
x = 1.5