To solve this system of equations, we can use the method of substitution or elimination.
First, let's rewrite the equations in standard form:
1) x + 2/3y = 22) 1/5x - y = 14
Now, we can use Equation 1 to express x in terms of y:
x = 2 - 2/3y
Next, we substitute this expression for x into Equation 2:
1/5*(2 - 2/3y) - y = 142/5 - 2/15y - y = 142/5 - 17/15y = 14
Now, we solve for y:
-17/15y = 14 - 2/5-17/15y = 70/5 - 2/5-17/15y = 68/5y = (68/5) / (-17/15)y = (68/5) * (-15/17)y = -102/17
Now that we have found the value of y, we can substitute it back into the expression we found for x earlier:
x = 2 - 2/3*(-102/17)x = 2 + 204/51x = 2 + 4x = 6
Therefore, the solution to the system of equations is x = 6 and y = -102/17.
To solve this system of equations, we can use the method of substitution or elimination.
First, let's rewrite the equations in standard form:
1) x + 2/3y = 2
2) 1/5x - y = 14
Now, we can use Equation 1 to express x in terms of y:
x = 2 - 2/3y
Next, we substitute this expression for x into Equation 2:
1/5*(2 - 2/3y) - y = 14
2/5 - 2/15y - y = 14
2/5 - 17/15y = 14
Now, we solve for y:
-17/15y = 14 - 2/5
-17/15y = 70/5 - 2/5
-17/15y = 68/5
y = (68/5) / (-17/15)
y = (68/5) * (-15/17)
y = -102/17
Now that we have found the value of y, we can substitute it back into the expression we found for x earlier:
x = 2 - 2/3*(-102/17)
x = 2 + 204/51
x = 2 + 4
x = 6
Therefore, the solution to the system of equations is x = 6 and y = -102/17.