Log2(3x-6)=log2(2x-10)

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вопрос

To solve this equation, we can first simplify by applying the properties of logarithms.

Since the bases of the logarithms are the same, we can drop them and set the expressions inside the logarithms equal to each other:

3x - 6 = 2x - 10

Now, we can solve for x by isolating x on one side of the equation:

3x - 2x = -10 + 6
x = -4

Therefore, the solution to the equation log2(3x-6) = log2(2x-10) is x = -4.