Expanding both sides of the equation:
(2x+3)(3x+1) + (5x+2)(2x+5) = 4x-1
First, expand the left side:
(2x+3)(3x+1) = 6x^2 + 2x + 9x + 3 = 6x^2 + 11x + 3
(5x+2)(2x+5) = 10x^2 + 25x + 4x + 10 = 10x^2 + 29x + 10
Combining the two expanded expressions:
6x^2 + 11x + 3 + 10x^2 + 29x + 10 = 4x - 1
Simplifying the equation:
16x^2 + 40x + 13 = 4x - 1
Rearranging the terms to set it equal to zero:
16x^2 + 40x - 4x -1 - 13 = 0
16x^2 + 36x -14 = 0
Which simplifies further to:
8x^2 + 18x - 7 = 0
Therefore, the equation (2x+3)(3x+1) + (5x+2)(2x+5) is indeed not equal to 4x-1.
Expanding both sides of the equation:
(2x+3)(3x+1) + (5x+2)(2x+5) = 4x-1
First, expand the left side:
(2x+3)(3x+1) = 6x^2 + 2x + 9x + 3 = 6x^2 + 11x + 3
(5x+2)(2x+5) = 10x^2 + 25x + 4x + 10 = 10x^2 + 29x + 10
Combining the two expanded expressions:
6x^2 + 11x + 3 + 10x^2 + 29x + 10 = 4x - 1
Simplifying the equation:
16x^2 + 40x + 13 = 4x - 1
Rearranging the terms to set it equal to zero:
16x^2 + 40x - 4x -1 - 13 = 0
16x^2 + 36x -14 = 0
Which simplifies further to:
8x^2 + 18x - 7 = 0
Therefore, the equation (2x+3)(3x+1) + (5x+2)(2x+5) is indeed not equal to 4x-1.