To solve the system of equations, we can first use the second equation to isolate one of the variables in terms of the other.
From the second equation, we have:x - y = 1x = y + 1
Now, we can substitute this expression for x into the first equation:3(y + 1) + 2y = 133y + 3 + 2y = 135y + 3 = 135y = 10y = 2
Now, we can substitute the value of y back into the equation x = y + 1 to find x:x = 2 + 1x = 3
Therefore, the solution to the system of equations is x = 3 and y = 2.
To solve the system of equations, we can first use the second equation to isolate one of the variables in terms of the other.
From the second equation, we have:
x - y = 1
x = y + 1
Now, we can substitute this expression for x into the first equation:
3(y + 1) + 2y = 13
3y + 3 + 2y = 13
5y + 3 = 13
5y = 10
y = 2
Now, we can substitute the value of y back into the equation x = y + 1 to find x:
x = 2 + 1
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 2.