Given sin a = -0.6, we can use the trigonometric identity:
sin^2(a) + cos^2(a) = 1
(-0.6)^2 + cos^2(a) = 10.36 + cos^2(a) = 1cos^2(a) = 1 - 0.36cos^2(a) = 0.64cos(a) = ±√0.64cos(a) = ±0.8
Since sin(a) and cos(a) have opposite signs in the second and third quadrants, where sin is negative, cos(a) will also be negative. Therefore, cos(a) = -0.8.
To find the value of tan(a), we can use the relationship:
tan(a) = sin(a)/cos(a)
tan(a) = -0.6 / -0.8tan(a) = 0.75
Therefore, cos(a) = -0.8 and tan(a) = 0.75.
Given sin a = -0.6, we can use the trigonometric identity:
sin^2(a) + cos^2(a) = 1
(-0.6)^2 + cos^2(a) = 1
0.36 + cos^2(a) = 1
cos^2(a) = 1 - 0.36
cos^2(a) = 0.64
cos(a) = ±√0.64
cos(a) = ±0.8
Since sin(a) and cos(a) have opposite signs in the second and third quadrants, where sin is negative, cos(a) will also be negative. Therefore, cos(a) = -0.8.
To find the value of tan(a), we can use the relationship:
tan(a) = sin(a)/cos(a)
tan(a) = -0.6 / -0.8
tan(a) = 0.75
Therefore, cos(a) = -0.8 and tan(a) = 0.75.