To solve the given equation, we will first isolate the term inside the parenthesis on the left side of the equation.
2log8(2-log2(x-3)) = 0
Next, we can rewrite the equation in exponential form:
8^0 = 2-log2(x-3)
Since anything raised to the 0 power equals 1, we have:
1 = 2-log2(x-3)
Now we can solve for x:
2-log2(x-3) = 1
-log2(x-3) = -1
Now, we can exponentiate both sides of the equation to get rid of the log:
2^(-1) = x-3
1/2 = x-3
x = 1/2 + 3
x = 3.5
Therefore, the solution to the equation 2log8(2-log2(x-3))=0 is x = 3.5.
To solve the given equation, we will first isolate the term inside the parenthesis on the left side of the equation.
2log8(2-log2(x-3)) = 0
Next, we can rewrite the equation in exponential form:
8^0 = 2-log2(x-3)
Since anything raised to the 0 power equals 1, we have:
1 = 2-log2(x-3)
Now we can solve for x:
2-log2(x-3) = 1
-log2(x-3) = -1
Now, we can exponentiate both sides of the equation to get rid of the log:
2^(-1) = x-3
1/2 = x-3
x = 1/2 + 3
x = 3.5
Therefore, the solution to the equation 2log8(2-log2(x-3))=0 is x = 3.5.