a^{-n}=1/a^n
Given that a=1/32, we substitute this value into the equation:
a^{-n}=1/(1/32)^a^{-n}=1/(1/32^na^{-n}=1*32^a^{-n}=32^n
a^{-n}=1/a^n
Given that a=1/32, we substitute this value into the equation:
a^{-n}=1/(1/32)^
a^{-n}=1/(1/32^n
a^{-n}=1*32^
a^{-n}=32^n