To solve this system of equations, we can use the substitution method.
First, isolate x in the second equation:x = y + 4
Now we can substitute this expression for x in the first equation:2(y + 4) + 3y = -72y + 8 + 3y = -75y + 8 = -75y = -15y = -3
Now that we have found the value of y, we can substitute it back into the equation x = y + 4 to find x:x = -3 + 4x = 1
Therefore, the solution to the system of equations is x = 1 and y = -3.
To solve this system of equations, we can use the substitution method.
First, isolate x in the second equation:
x = y + 4
Now we can substitute this expression for x in the first equation:
2(y + 4) + 3y = -7
2y + 8 + 3y = -7
5y + 8 = -7
5y = -15
y = -3
Now that we have found the value of y, we can substitute it back into the equation x = y + 4 to find x:
x = -3 + 4
x = 1
Therefore, the solution to the system of equations is x = 1 and y = -3.