2x - 10 + 4 = -2x^2 - 6x + 4

2x - 6 = -2x^2 - 6x + 4

Rearranging terms:

2x - 6 + 6x - 4 = -2x^2

8x - 10 = -2x^2

Rearranging terms again:

2x^2 + 8x - 10 = 0

Now, we can solve this quadratic equation using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 2, b = 8, c = -10:

x = (-8 ± √(8^2 - 42(-10))) / (2*2)

x = (-8 ± √(64 + 80)) / 4

x = (-8 ± √144) / 4

x = (-8 ± 12) / 4

So, the solutions are:

x = (-8 + 12) / 4 = 4 / 4 = 1

or

x = (-8 - 12) / 4 = -20 / 4 = -5

Therefore, the solutions to the equation 2(х-5) + 4 = -2х(х+3) + 4 are x = 1 and x = -5.