(40,2+х):(-2,5)=-113/5

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вопрос

To find the equation of the line passing through the points (40, 2 + x) and (-2, 5), we first need to find the slope of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Substitute the values of the points into the formula:

m = (5 - (2 + x)) / (-2 - 40
m = (5 - 2 - x) / (-42
m = (3 - x) / (-42
m = (3 - x) / -42

Now, we can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Choose one of the points to substitute into the equation. Let's use (40, 2 + x):

y - (2 + x) = (3 - x) / -42) (x - 40)

Now, simplify the equation:

y - 2 - x = (3 - x) / -42 (x - 40
y = (3 - x) / -42 (x - 40) + x + 2

Therefore, the equation of the line passing through the points (40, 2 + x) and (-2, 5) is:

y = (3 - x) / -42 (x - 40) + x + 2