21x-3y=15 4m-5n=1
{4x+3y=10 {2m-3n=2

Предыдущий
вопрос Следующий
вопрос

To solve the system of equations, we can use the method of substitution or elimination. Let's solve it using the method of substitution.

From the first equation, we can rearrange it to solve for x:
21x - 3y = 15
21x = 3y + 15
x = (3/21)y + 15/21
x = (1/7)y + 5/7

Now substitute this back into the second equation:
4(1/7)y + 3y = 10
(4/7)y + 3y = 10
(25/7)y = 10
y = (7/25) * 10
y = 2.8

Now that we have the value of y, we can substitute it back into the first equation to find x:
21x - 3(2.8) = 15
21x - 8.4 = 15
21x = 23.4
x = 23.4 / 21
x = 1.114

Therefore, the solution to the first system of equations is x = 1.114 and y = 2.8.

Now let's solve the second system of equations using the same method:

From the third equation, we can rearrange it to solve for m:
4x + 3y = 10
4x = 10 - 3y
x = (10/4) - (3/4)y
x = 2.5 - (3/4)y

Now substitute this back into the fourth equation:
2(2.5 - (3/4)y) - 3n = 2
5 - (3/2)y - 3n = 2
(3/2)y + 3n = 3
(3/2)y = 3 - 3n
y = 2 - 2n

Now that we have the value of y in terms of n, we can substitute it back into x and solve for m. The solution in this case would be in terms of n and m, as the system is not uniquely solvable.