1) Сх^2=Cx^x-1 2) (n+1)!/n!=5

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вопрос

1) To simplify the equation, we can divide both sides by x^x-1:

Simplify: c = C

So, the equation simplifies to c = C.

2) (n+1)! / n! = 5

(n+1)! = 5n!

Since (n+1)! = (n+1) * n!, we can distribute on the left side:

(n+1) * n! = 5n!

Simplify further by dividing both sides by n!:

n+1 = 5

Therefore, the solution to the equation is n = 4.