To find the solutions to these quadratic equations, we can use the quadratic formula which states that for an equation of the form ax^2 + bx + c = 0, the solutions are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

1)

For the equation x^2 + 3x - 2 = 0, we have a = 1, b = 3, and c = -2.

Using the quadratic formula:

x = (-3 ± √(3^2 - 41(-2))) / 2*1
x = (-3 ± √(9 + 8)) / 2
x = (-3 ± √17) / 2

So, the solutions to x^2 + 3x - 2 = 0 are x = (-3 + √17) / 2 and x = (-3 - √17) / 2.

2)

For the equation -x^2 - 3x + 2 = 0, we have a = -1, b = -3, and c = 2.

Using the quadratic formula:

x = (3 ± √((-3)^2 - 4(-1)2)) / 2*(-1)
x = (3 ± √(9 + 8)) / -2
x = (3 ± √17) / -2

So, the solutions to -x^2 - 3x + 2 = 0 are x = (3 + √17) / -2 and x = (3 - √17) / -2.