In order to solve this inequality, we need to consider two cases:

Case 1: log1,7(5-2x) > 0 and log2(0,1) > 0
For logarithmic functions to be positive, the argument inside the logarithm must be greater than 1.
So, we have:
5 - 2x > 1
-2x > -4
x < 2

However, the second logarithmic function log2(0,1) is undefined as the base 2 logarithm of 1 is equal to 0. Therefore, this case does not have a valid solution.

Case 2: log1,7(5-2x) < 0 and log2(0,1) < 0
For logarithmic functions to be negative, the argument inside the logarithm must be between 0 and 1 exclusive.
So, we have:
0 < 5 - 2x < 1
5 > 2x > 4
5/2 > x > 2

However, as mentioned before, the second logarithmic function log2(0,1) is undefined and does not satisfy this case either.

Therefore, there are no solutions to the inequality (log1,7(5-2x))/log2(0,1) > 0.