3-2x^2+5x=0

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вопрос

To solve this quadratic equation, we can first rearrange it into standard form:

-2x^2 + 5x + 3 = 0

Next, we can use the quadratic formula to find the roots of the equation. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the roots are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = -2, b = 5, and c = 3. Plugging these values into the formula, we get:

x = (-5 ± √(5^2 - 4(-2)(3))) / 2(-2
x = (-5 ± √(25 + 24)) / -
x = (-5 ± √49) / -
x = (-5 ± 7) / -4

This gives us two possible roots:

x = (-5 + 7) / -4 = 2 / -4 = -0.5

x = (-5 - 7) / -4 = -12 / -4 = 3

Therefore, the roots of the equation 3 - 2x^2 + 5x = 0 are x = -0.5 and x = 3.