Решите систему уравнений способом подстановки 15x+2(x + 3y)=3(4x+y) , 2(5x-y)-3y=2+3(2x-y)

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вопрос

1) 15x + 2(x + 3y) = 3(4x + y)
15x + 2x + 6y = 12x + 3y
17x + 6y = 12x + 3y
17x - 12x = 3y - 6y
5x = -3y
x = -3y/5

2) 2(5x - y) - 3y = 2 + 3(2x - y)
10x - 2y - 3y = 2 + 6x - 3y
10x - 5y = 2 + 6x - 3y
10(-3y/5) - 5y = 2 + 6(-3y/5) - 3y
-6y - 5y = 2 - 18y/5 - 3y
-11y = 2 - 18y/5 - 3y
-11y = 2 - 18y/5 - 15y/5
-11y = 2 - 33y/5
-55y = 10 - 33y
-55y + 33y = 10
-22y = 10
y = -10/22
y = -5/11

Now we can substitute y in the first equation to find x:
x = -3(-5/11)/5
x = 15/11
x = 15/11

Therefore, the solution to the system of equations is:
x = 15/11
y = -5/11