To solve this system of equations, we can use the method of elimination.
First, let's rewrite the equations in standard form:
-5a + 3b - 4c = 504a - b - 3c = -2-3a + 4b + 3c = 14
Now, let's eliminate one variable at a time.
-20a + 12b - 16c = 20020a - 5b - 15c = -10
Adding these two equations together, we get:
7b - 31c = 190
-15a + 9b - 12c = 150-15a + 20b + 15c = 70
29b + 3c = 220
16a - 4b - 12c = -8-15a + 20b + 15c = 70
a + 3c = 62
Now, we have the following new system of equations:
7b - 31c = 19029b + 3c = 220a + 3c = 62
Solving this system of equations will give us the values of a, b, and c.
To solve this system of equations, we can use the method of elimination.
First, let's rewrite the equations in standard form:
-5a + 3b - 4c = 50
4a - b - 3c = -2
-3a + 4b + 3c = 14
Now, let's eliminate one variable at a time.
Let's eliminate "a" from the first two equations by multiplying the first equation by 4 and the second equation by 5:-20a + 12b - 16c = 200
20a - 5b - 15c = -10
Adding these two equations together, we get:
7b - 31c = 190
Next, let's eliminate "a" from the first and third equations. Multiply the first equation by 3 and the third equation by 5:-15a + 9b - 12c = 150
-15a + 20b + 15c = 70
Adding these two equations together, we get:
29b + 3c = 220
Finally, let's eliminate "b" from the last two equations. Multiply the second equation by 4 and the third equation by 5:16a - 4b - 12c = -8
-15a + 20b + 15c = 70
Adding these two equations together, we get:
a + 3c = 62
Now, we have the following new system of equations:
7b - 31c = 190
29b + 3c = 220
a + 3c = 62
Solving this system of equations will give us the values of a, b, and c.