Log3(1-6x)=log3(17-x2)

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To solve this equation, we can remove the logarithms by using the property of logarithms that states that if log(a) = log(b), then a = b.

Therefore, we have:

1 - 6x = 17 - x^2

Rearranging the equation, we get:

x^2 - 6x + 16 = 0

Now, we can factor this quadratic equation:

(x - 4)(x - 4) = 0

Therefore, the solution to the equation is x = 4.