3 ^(2х-6х+3)+6 ^(х2-3х+1)= 2 ^(2х2-6+3)

Предыдущий
вопрос Следующий
вопрос

First, let's simplify the exponents:

3^(2x-6x+3) = 3^(-4x+3) = 1/(3^(4x-3))

6^(x^2-3x+1) = 6^(-3x+1)

2^(2x^2-6+3) = 2^(2x^2-3)

Now, let's rewrite the equation with the simplified exponents:

1/(3^(4x-3)) + 6^(-3x+1) = 2^(2x^2-3)

Now, we need to choose an approach to solve for x. We can take the logarithm on both sides, or we could try to simplify further. Let's first try to simplify further:

1/(3^(4x-3)) + 6^(-3x+1) = 2^(2x^2-3)

1/(3^(4x) 3^(-3)) + 1/6^(3x) = 1/2^(3) 2^(2x^2)

3^3/3^(4x) + 1/6^(3x) = 1/2^(3) * 2^(2x^2)

27/3^(4x) + 1/6^(3x) = 1/8 * 2^(2x^2)

((276^3)/3^(4x)) + 1/6^(3x) = 1/8 2^(2x^2)

Now we can simplify further or take the logarithm on both sides.